Вопрос от пользователя: Авдуся
Вычислить: (2^-1 + 3^-1) (2^-1 — 3^-1) + (2^-1 ∙2^0) ^-4 : 2^3
Ответ: Екатерина
1) 1/4=0.25, 0.25-0.2=0.05 или 0.2=2/10=1/51/4 — 1/5 = (5-4) / 20=1/20=0.2
2) — 3/7 + 1/5 = (-3*5+7) / 35 = (-15+7) / 35 = — 8/35
3) 1.5=1 5/10=1 1/2=3/2-1/3 * 3/2 = (-1*3) / 3*2 = — 3/6 = — 1/2 = — 0.5
4) при делении дробь переворачиваем и будет умножение 0.36=36/100=9/259/25 * (-19/18) = (-9*19) / (25*18) = — 19/25*2 = — 19/50 = — 0.38
5) 3 1/2=7/2=3.52.3=23/10-7/2 + 23/10 = (-7*5+23) / 10 = (-35+23) / 10 = — 12/10 = — 1.2 или — 3.5 + 2.3 = — 1.2
6) 2 1/3=7/3, 4.1=41/107/3 — 41/10 = (70-123) / 30 = = — 53/10 = — 5.3
7) 1 6/10=1 3/5=8/511/4 * 8/5=11*8 / 4*5 = 22/5 = 4.4
8) 1 1/4=5/4, 6.25=6 25/100 = 6 1/4 = 25/4-25/4 * 4/5 = — 25*4 / 4*5 = — 5
9) 3 19/20=79/205 1/5=26/55.25=5 1/4=21/41.4=1 4/10=1 2/5=7/5-21/4 : (26/5 — (5/7 * 7/5) — 79/20 = — 21/4 : (26/5 — 1) — 79/20 = — 21/4 : 21/5 — 79/20 = — 21/4 * 5/21 — 79/20 = = — 5/4 — 79/20 = (-25-79) / 20 = — 104/20 = — 5.2
